Question

if the resistance triples at constant current. What will happen to the power dissipated in the resistor​

Answer 1

Explanation:

$p = v { }^{2} \div r$

$r (new) = 3r$

$p (new)= v {}^{2} \div 3r$

$= 1 \div 3(p)$

Hence power become 1/3 times the original