Question

if the resultant is 0.6 times the magnitude of two equal forces then the angle between the forces is

Answer 1

Answer:

0.6r=√r^2+r^2+2r.r.cos theta

0.36r^2=2r^2+2r^2 cos theta

-1.64/2=cos theta

-0.82=cos theta

theta=cos^-1(-0.82)

Answer 2

Answer:

R^2= A^2+B^2+2ABcosx= 2A^2+2A^2cosx

(A/2)^2 = 2A^2(1+ cosx)

1/8= 1+cosx

-7/8= cosx=

7/8= cos{180°- X)

(180°-x) = 29°

X= 151°