if the resultant of the two forces 3N and 4N acting at a point is 5N, then the angle between two forces will be
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Solution :-
As we know that ,
♦ R = √ A² + B² + 2AB cosθ
Simplifying ,
♦ R² = A² + B² + 2AB cosθ
Where,
- R is the resultant force = 5N
- A & B are the forces acted [ A = 3N & B = 4N ]
- θ is the angle between the forces
Substituting the known values we have ,
➵ 5² = 3² + 4² + 2 × ( 3 ) × ( 4 ) × cosθ
➵ 25 = 9 + 16 + 24cosθ
➵ 25 = 25 + 24 cosθ
➵ 25 - 25 = 24 cosθ
➵ 0 = 24 cosθ
➵ 0/24 = cosθ
➵ 0 = cosθ
Substituting , 0 = cos90°
➵ cos90° = cosθ
By comparision ,
➵ θ = 90° = Angle between the forces
Hence , angle between the forces = 90°
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