if the resultant of two forces 6n and 8n is 12n find the angle between them?
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Answer:
cos⁻¹ ( 11 / 24 )
Explanation:
Given :
F₁ = 6 N
F₂ = 8 N
Resultant Force = 12 N
We have to find angle :
We know :
R = √ ( F₁² + F₂² + 2 F₁ F₂ cos Ф )
Squaring on both side :
R² = ( F₁² + F₂² + 2 F₁ F₂ cos Ф )
Putting value here we get :
12² = 6² + 8² + 2 . 6 . 8 . cos Ф
144 - 100 = 96 cos Ф
cos Ф = 44 / 96
cos Ф = 11 / 24
Ф = cos⁻¹ ( 11 / 24 )
Therefore , angle between them is cos⁻¹ ( 11 / 24 ).
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