if the resultant of two unequal vectors is equal to sum of their magnitudes what is the angle between vectors ?
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Answered by
59
Let A and B be two unequal vectors and θ be the angle between them.Therefore according to given :
A+B=√(A²+B²+2ABcos θ)
Squaring on both sides, we get
(A+B)²=A²+B²+2ABcos θ
A²+B²+2AB=A²+B²+2ABcos θ
2AB=2ABCosθ
Cosθ=1
∴ Cosθ=Cos0°
∴ θ=0°
A+B=√(A²+B²+2ABcos θ)
Squaring on both sides, we get
(A+B)²=A²+B²+2ABcos θ
A²+B²+2AB=A²+B²+2ABcos θ
2AB=2ABCosθ
Cosθ=1
∴ Cosθ=Cos0°
∴ θ=0°
Answered by
4
Answer:
0 degree
Explanation: R=A+B(A is not equal B)
A+B=√(A²+B²+2ABcos θ)
Squaring on both sides, we get
(A+B)²=A²+B²+2ABcos θ
A²+B²+2AB=A²+B²+2ABcos θ
2AB=2ABCosθ
Cosθ=1
∴ Cosθ=Cos0°
∴ θ=0°
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