If the resultant of two unequal vectors is equal to sum of their magnitudes find the angle between the vectors
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Let A and B be two unequal vectors and θ be the angle between them.Therefore according to given :
A+B=√(A²+B²+2ABcos θ)
Squaring on both sides, we get
(A+B)²=A²+B²+2ABcos θ
A²+B²+2AB=A²+B²+2ABcos θ
2AB=2ABCosθ
Cosθ=1
∴ Cosθ=Cos0°
∴ θ=0°
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