if the right angle traingle ABC,A=60° and BC=6cm ,find AB and AC
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HI !
In Δ ABC , right angled at B ,
∠ C = 180 - (90 + 60) = 30°
tan 60° = BC/AB
√3 = 6/AB
AB = 6/√3
AB = 2√3 cm
Also,
sin 60° = BC/AC
√3/2 = 6/AC
√3 AC = 12
AC = 12/√3
AC = 4√3 cm
---------------------------------------------
AC = 4√3 cm and AB = 2√3 cm
In Δ ABC , right angled at B ,
∠ C = 180 - (90 + 60) = 30°
tan 60° = BC/AB
√3 = 6/AB
AB = 6/√3
AB = 2√3 cm
Also,
sin 60° = BC/AC
√3/2 = 6/AC
√3 AC = 12
AC = 12/√3
AC = 4√3 cm
---------------------------------------------
AC = 4√3 cm and AB = 2√3 cm
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Jitesh111:
thank you for your help wish you good for your srudy
hehe thanks ^_^
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