if the right triangle ∆ABC tan theta = 12/5 find sin theta
nikitaparihsr:
sin theta =12/13
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Answered by
25
given, tanQ = 12/5
so , PERPENDICULAR / BASE = 12/5 hence
perpendicular = 12 and base = 5
applying Pythagoras theorem
(hypotenuse) square = (12) square +(5) square
(hypotenuse) square = 144 +25
(hypotenuse ) square = 169
so (hypotenuse ) = 13
therefore sinQ= p/b
sinQ =12/13
so , PERPENDICULAR / BASE = 12/5 hence
perpendicular = 12 and base = 5
applying Pythagoras theorem
(hypotenuse) square = (12) square +(5) square
(hypotenuse) square = 144 +25
(hypotenuse ) square = 169
so (hypotenuse ) = 13
therefore sinQ= p/b
sinQ =12/13
Answered by
11
sin theta is equal to 12/13
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