If the root is equal to the square of other root of the equation x *2+x-k=0 then k is
Answers
Answered by
1
Answer:
2✖️x✖️root x
Step-by-step explanation:
(x-root x)*2=x*2+x-k
x*2+x-2✖️x✖️root x=x*2+x-k
2✖️x✖️root x=k
Similar questions