If the root of 2x^2-6x+k=0 are ral and equal find k
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as D = 0
D = b^2 - 4ac =0
D = (-6)^2 - 4 (2)(k) =0
D = 36 - 8K = 0
D = 36 = 8K
K = 36/8 = 9/2
hey mate.
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D = b^2 - 4ac =0
D = (-6)^2 - 4 (2)(k) =0
D = 36 - 8K = 0
D = 36 = 8K
K = 36/8 = 9/2
hey mate.
here is the answer.
hope it helps you.
if you like it please mark it as brainliest.
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