Question

if the root of 2xsquare _ 6x+ k=0 are real and equal ,find k

Answer 1

√2x²-6x+k=0
for real and equal roots
D(discriminant)=0 or greater then 0
b²-4ac=0 [a=√2, b=-6 ,and c=k]
(-6)²-4(√2)(k)=0
36-4√2k=0
-4√2k=-36
sign of minis on both side will be cut
4√2k=36
√2k=36/4
√2k=9
k=9/√2

Hope it is helpful