Question

if the root of 2xsquare -6x+k=0are real and equal ,find k

Answer 1

discriminant = 0
b^2 - 4ac=0
36 - 8k = 0

k = 9/2...........

Answer 2

Answer:

k = 9/2

Step-by-step explanation:

Given Equation is 2x² - 6x + k = 0.

On comparing with ax² + bx + c = 0, we get a = 2, b = -6, c = k.

Given that the equation has real and equal roots.

∴ Δ = 0

⇒ b² - 4ac = 0

⇒ (-6)² - 4(2)(k) = 0

⇒ 36 - 8k = 0

⇒ 36 = 8k

⇒ k = 36/8

⇒ k = 9/2.

Therefore, the value of k = 9/2.

Hope it helps!