Math, asked by syedrazamisbahi2165, 6 months ago

If the root of quadratic equation are -2 and -3 from the equation

Answers

Answered by tennetiraj86
0

Step-by-step explanation:

given \: roots \: are \:  - 2 \: and \:  - 3 \\  \: let \:  \alpha  =  - 2 \: and \:  \beta  =  - 3 \\  \: we \: know \: that \\  \: if \:  \alpha  \: and \:  \beta  \: are \: the \: roots \: then \: the \: quadratic \: equation \: is \:  \\  \:  {x}^{2}  - ( \alpha  +  \beta )x +  \alpha  \beta  = 0 \\  \:  =  >  {x}^{2}  - ( - 2 - 3)x + ( - 2)( - 3) = 0 \\  \:  =  >  {x}^{2}- ( - 5)x + 6 = 0 \\  \:  =  >  {x}^{2}  + 5x + 6 = 0 \\  \: required \: quadratic \: equation \:is \:  {x}^{2}  + 5x + 6 = 0

Answered by udaykushwaha2004
0

x²+5x+6 is the answer....

Similar questions