Question

if the root of quadratic equation are 2 and -5, then the quadratic equation is​

Answer 1

Step-by-step explanation:

given that 2 and -5 are roots of a quadratic eq.

let the variable of the quadratic eq. be 'x'

=> x=2 and x=-5

=> x-2=0 and x+5=0

so (x-2) and (x+5) are factors of the quadratic eq.

=> quadratic equation is:

(x-2)(x+5) =

${x}^{2} + 3x - 10$

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Answer 2

Answer:

x^2 + 3x - 10

Step-by-step explanation:

The Quadr. Eqn. having roots αandβ is given by,

(x−α)(x−β)=0,

x^2−(α+β)x+(α⋅β)=0.

As α=2andβ=−5, it follows that, the desired equation is ,

=x^2 − (2 − 5) x + (2) (−5)

= x^2 + 3x - 10

HOPE IT HELPS U ✌