Question

if the root of the equation 5x^2 +mx+5=0 , real and equal find the value of m

Answer 1

Answer:

Step-by-step explanation:

If roots are real and equal then discriminant is equal to zero

Discriminant=b²-4ac

5x²+mx+5

Here a= 5

b=m

c=5

m²-4×5×5=0

m²-100=0

m²=100

m=√100

m=10,-10

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Answer 2

Given that roots are real and equal then D=0

D=sqa.root of b^2-4ac

b=m

a=5 c=5

D=sqa.root of m^2-100

According to the question,

D=0

Sqa.root of m^2-100=0

m^2-100=0

m^2=100

m=10