Question

if the root of x^2+kx+k=0 are real and equal, what is the value of k?
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Answer 1

Answer:

Given:-x^2+kx+k=0

To Find Value of K

Step-by-step explanation:

Roots for real and equal D should be equal to zero.

so,

=> b²-4ac=0

=> k²-4k=0

=> k(k-4)=0

=> k-4=0

=> k=4

Hence k is equal to 4.