Math, asked by Shoaeeb7818, 11 months ago

If the root of x2+kx+k=0 are real and equal what is the value of k

Answers

Answered by Rudra0936
7

Step-by-step explanation:

refer to the attachment

Attachments:
Answered by abhi569
3

Answer:

0 or 4

Step-by-step explanation:

To roots to be real and equal, discriminant of the equation must be 0.

Discriminant of ax² + bx + c = 0 is given by b² - 4ac.   On comparing,

a = 1,   b = k,     c = k

  ⇒ discriminant = 0

  ⇒ k² - 4(1)(k) = 0

  ⇒ k² - 4k = 0

  ⇒ k(k - 4) = 0

  ⇒ k = 0    or  k - 4 = 0

  ⇒ k = 0    or  k = 4

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