If the roots of 2x squar - 6x + k = 0 are real and equal, find k.
Answers
Answered by
0
b square - 4×a×c=0
-6×-6-4×2×k=0
36 - 8 × k =0
-8k = -36
8k= 36
k= 9÷2
-6×-6-4×2×k=0
36 - 8 × k =0
-8k = -36
8k= 36
k= 9÷2
Jocker95:
This is wrong because 8k is multiple and 36 is also addeble.
Answered by
2
2x^2-6x+k=0
a=2 b=-6 c=k
roots are real and equal
b^2-4ac=0
(-6)^2-4×2×k=0
36-8k=0
-8k=-36
k=-36/-8
k=9/2
sry ur answer is right
pls say me how to keep pic
pls ruchi
go in me
there is a + sign in the circle
touch it then
there is a two options
first option choose
and set your pic
plzz mark as brainlist
Similar questions