If the roots of 2x²- 6x + k = 0 are real and equal find k.
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Answered by
10
by comparing the equation ax^2 + bx + c
a = 2
b = 6
c = k
as the roots are real and equal
hence
b^2 = 4ac
6^2 = 4 ×2 × k
36 = 8k
therefore k is equal to 9/2
a = 2
b = 6
c = k
as the roots are real and equal
hence
b^2 = 4ac
6^2 = 4 ×2 × k
36 = 8k
therefore k is equal to 9/2
marianfrancis47:
I have attached the feather step of
36=8k
Answered by
1
Answer: 9/2
Step-by-step explanation:
For real roots Descrimnant (D) must be greater then 0
D = √( 36- 8k)
√ ( 36-8k ) >0
Squaring both sides
36 > 8k
k < 36/8
k < or equal to9/2
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