Question

If the roots of 2z^2-6x+k =0 are real and equal the find k​

Answer 1

Answer:

k=9/2

Step-by-step explanation:

2x²-6x+k =0

here a=2,b=-6,c=k

the roots will be real and equal if

b²=4ac

(-6)²=4*2*k

36=8k

k=36/8=9/2

Answer 2

⊱✿ αɳടɯҽɾ ✿⊰

The roots of the quadratic equation are real and equal :-

➨b² - 4ac = 0

➨(-6)² - 4×2×k = 0

➨-8k = -36

➨K = 9/2