If the roots of 3x + 8x + 2 = 0 are a and 8, then (a '+ B) =?
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Step-by-step explanation:
Comparing 3x² + 8x + 2 = 0 with ax² + bx + c = 0:
a = 3, b = 8 and c = 2.
Hence (a + β) = - b / a
= – 8/3
and aβ = c / a
= 2/3.
Hence (a³+ β³)
= (a +β)³ - 3aβ (a + β)
= (-8/3)³ - 3 × 2/3 × (-8) / 3
= (-512/27) + (16 / 3)
= (-512 + 144) / 27
= - 368/27.... Answer
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