Question

If the roots of 5x - kx + 1 = 0 are real and distinct then​

Answer 1

if the roots of 5x2-kx+1=0 are real and distinct then. Solution : The roots of 5x2-kx+1=0 are real and distinct. ⇒k>2√5 or k<-2√5

Answer 2

Equation quadratic hogi aapne galat type kiye hoge.

$5 {x}^{2} - kx + 1 = 0$

Now Since the roots are real and distinct.

Therefore D>0

$= > \: {b}^{2} - 4ac > 0 \\ = > {k}^{2} - 4 \times 5 \times 1 > 0 \\ = > {k}^{2} - 20 > 0 \\ = > {k}^{2} > 20 \\ = > k > \sqrt{20}$

Therefore all the values of above 2√5 are values of k.

Hope it is helpful