If the roots of 9x²+(k-2)x-9=0, the find the value of k?
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Heyy mate ❤✌✌❤
Here's your Answer....
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Since, it is equal to 0.
=> D = 0
=> b^2 - 4ac =0
=>( k-2)^2 - 4× 9 × 9
=> k^2 + 4 - 4k - 324 =0
=> k^2 - 4k - 320 = 0
=> k( k - 4) - 320 = 0
=> k -4 = 320
=> k = 320 + 4
=> k = 324.
✔✔✔
Here's your Answer....
⤵️⤵️⤵️⤵️⤵️⤵️⤵️⤵️
Since, it is equal to 0.
=> D = 0
=> b^2 - 4ac =0
=>( k-2)^2 - 4× 9 × 9
=> k^2 + 4 - 4k - 324 =0
=> k^2 - 4k - 320 = 0
=> k( k - 4) - 320 = 0
=> k -4 = 320
=> k = 320 + 4
=> k = 324.
✔✔✔
sanjaysarthakmishra:
thanks
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