Question

If the roots of a(b-c) x²+b(c-a) x+c(a-b) = 0 are having equal roots then a, b, c are in

Answer 1

Answer:

Since coeffs add up to zero, 1 is a root

Since roots are equal, P = 1*1 = 1

Or c(a-b) / a(b-c) = 1

ac -bc = ab -ac

2ac = b(a+c)

Answer 2

Answer:

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