If the roots of (a2 + b2)x2 – 2b(a + c)x + (b2 + c2) = 0 are equal, show that a,b,c are in G.P.
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The roots of the equation (a² + b²)x² - 2b(a + c)x + (b² + c²) = 0 are equal. here in question, the roots of equation are equal. Therefore the option (b) b² = ac, is correct choice.
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I think answer is G.P
Step-by-step explanation:
The roots of (a2+b2)x2−2b(a+c)x+(b2+c2)=0 are equal.
i.e. D=b2−4ac=0
⇒4b2(a+c)2=4(a2+b2)(b2+c2)
⇒b2(a2+c2+2ac)=a2b2+a2c2+b4+b2c2
⇒b2a2+b2a2+2ab2c=a2b2+a2c2+b4+b2c2
⇒b4−2b2ac+a2c2=(b
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