if the roots of ax2+bx-3=0 are reciprocal of each other then
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To Find :- Value of a ?
Solution :-
comparing the given quadratic equation with ax² + bx + c = 0 , we get,
- a = a
- b = b
- c = (-3)
let us assume that, roots of given quadratic equation are p and q .
so,
→ p = 1/q { roots are reciprocal of each other. }
→ p * q = (1/q) * q = 1 ------ Eqn.(1)
now,
→ product of roots = c/a
→ p * q = (-3)/a
from Eqn.(1) ,
→ 1 = (-3)/a
→ a = (-3) (Ans.)
Hence, value of a is equal to (-3) .
Note :- when the roots of quadratic equation ax² + bx + c = 0 are reciprocal of each other :-
- a = c .
Learn more :-
solution of x minus Y is equal to 1 and 2 X + Y is equal to 8 by cross multiplication method
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