if the roots of equation 2x^2-6x+k=o are real and equal then what is the value of k?
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We know that,for a quadratic equation when the discrimant is equal to zero,the roots are real and equal.
Following these criteria, in the given equation 2x^2-6x+k=0, discriminant is √(b^2-4ac),where b=-6 , a=2,c=k.
therefore,discriminant = √(36-(4)(2)(k) = 0
8k=36
k=9/2
Following these criteria, in the given equation 2x^2-6x+k=0, discriminant is √(b^2-4ac),where b=-6 , a=2,c=k.
therefore,discriminant = √(36-(4)(2)(k) = 0
8k=36
k=9/2
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