Question

if the roots of equation (a-b)x^2 + (b-c)x + (c-a) = 0 are equal , prove that 2a = b+c​

Answer 1

Answer:

this is the appropriate answer for this question.

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Answer 2

Answer:

Answer:if the roots of equation (a-b)x^2+(b-c)x+(c-a)=0are equal,prove that 2a=b+c?

Answer:if the roots of equation (a-b)x^2+(b-c)x+(c-a)=0are equal,prove that 2a=b+c?Step-by-step explanation:

Answer:if the roots of equation (a-b)x^2+(b-c)x+(c-a)=0are equal,prove that 2a=b+c?Step-by-step explanation:USING. DISCRIMINANT .

Answer:if the roots of equation (a-b)x^2+(b-c)x+(c-a)=0are equal,prove that 2a=b+c?Step-by-step explanation:USING. DISCRIMINANT . D =b^2-4a as compared with the general quadratic equations

• Answer:if the roots of equation (a-b)x^2+(b-c)x+(c-a)=0are equal,prove that 2a=b+c?Step-by-step explanation:USING. DISCRIMINANT . D =b^2-4a as compared with the general quadratic equationsAx^2+bx+c=0
• Answer:if the roots of equation (a-b)x^2+(b-c)x+(c-a)=0are equal,prove that 2a=b+c?Step-by-step explanation:USING. DISCRIMINANT . D =b^2-4a as compared with the general quadratic equationsAx^2+bx+c=0 so
• Answer:if the roots of equation (a-b)x^2+(b-c)x+(c-a)=0are equal,prove that 2a=b+c?Step-by-step explanation:USING. DISCRIMINANT . D =b^2-4a as compared with the general quadratic equationsAx^2+bx+c=0 so A= a-b
• Answer:if the roots of equation (a-b)x^2+(b-c)x+(c-a)=0are equal,prove that 2a=b+c?Step-by-step explanation:USING. DISCRIMINANT . D =b^2-4a as compared with the general quadratic equationsAx^2+bx+c=0 so A= a-b B= b-c
• Answer:if the roots of equation (a-b)x^2+(b-c)x+(c-a)=0are equal,prove that 2a=b+c?Step-by-step explanation:USING. DISCRIMINANT . D =b^2-4a as compared with the general quadratic equationsAx^2+bx+c=0 so A= a-b B= b-c C = c-a

for root to be equal ,D=0

(b-c)^2-4(a-b)(c-a)=0

b^2+c^2-2bc-4(ac-a^2-bc+ab)=0

b^2+c^2-2bc-4ac+4a^2+4bc-4ab=0

4a^2+b^2+c^2+2bc-4ab -4ac=0

(2a-b-c)^2=0

i.e.2a-b-c=0 =2a=b+c

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