Question

if the roots of equation x2-(2m+1) x +(2m-1)=0 are equal magnitude but opposite sign, then the value of m is?​

Answer 1

Answer:

(2m+1)^2 = 4×1×(2m-1)

(2m+1) = +4(2m-1) = -4(2m-1)

4(2m-1) = -4(2m - 1)

2m -1 = -(2m-1)

2m -1 +2m -1 = 0

4m - 2 = 0

m = 2/4 = 1/2 Ans