If the roots
of given Quadratic equation
are real
+ equal
Find the value of k.
kx (2-2) + 6 =0
Answers
Answered by
2
Answer:
kx(x−2)+6=0
kx
2
−2kx+6=0
Since the roots are equal,
⇒b
2
=4ac
(−2k)
2
=4(k)(6)
4k
2
=4k(6)
∴k=6
Step-by-step explanation:
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