Question

If the roots of kx(x-2)+6=0 are equal the find k value?​

Answer 1

Step-by-step explanation:

If kx(x-2)+6=0

kx^2 -2kx +6=0

by using dicrimant formula i.e

b^2-4ac

b^2-4ac=0

(-2k)^2 -4×k×6=0

4k^2 -24k=0

4k(k -6)=0

therefore,k=0 or k=6

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Answer 2

Answer:

• k = 0 or 6.

Step-by-step explanation:

Given:

• Roots of quadratic equation kx(x - 2) + 6 are equal.

To Find:

• Value of k.

We know that when b² - 4ac = 0, then the quadratic equation has equal roots.

⇒ kx(x - 2) + 6 = 0

⇒ kx² - 2kx + 6 = 0

Where,

• a = k
• b = -2k
• c = 6

⇒ (-2k)² - 24k = 0

⇒ 4k² - 24k = 0

⇒ 4k(k - 6) = 0

________________

⇒ k - 6 = 0

⇒ k = 6

________________

⇒ 4k = 0

⇒ k = 0

Hence, k = 0 or 6.

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