Question

if the roots of kx (x-2) +6=0are equal then find k value​

Answer 1

Answer:

Step-by-step explanation:

Kx^2-2kx+6=0

B^2-4ac=0

-2k^2-4*k*6=0

4k^2-24k=0

4k(k-6)=0

Therefore K=6