Question

if the roots of quadratic equation 2x²-kx+k=0 are real and equal then find the value of k​

Answer 1

ompare given Quadratic equation 2x²-kx+k=0 with ax²+bx+c=0, we get

a = 2,b = -k , c = k,

Discreminant (D)=0

[ Given roots are equal ]

=> b²-4ac=0

=> (-k)²-4×2×k=0

=> k²-8k=0

=> k(k-8)=0

=> k = 0 or k=8

Therefore,

Value \:of \: k = 0 \:or\:8Valueofk=0or8