if the roots of quadratic equation 2x²-kx+k=0 are real and equal then find the value of k
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ompare given Quadratic equation 2x²-kx+k=0 with ax²+bx+c=0, we get
a = 2,b = -k , c = k,
Discreminant (D)=0
[ Given roots are equal ]
=> b²-4ac=0
=> (-k)²-4×2×k=0
=> k²-8k=0
=> k(k-8)=0
=> k = 0 or k=8
Therefore,
Value \:of \: k = 0 \:or\:8Valueofk=0or8
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