if the roots of quadratic equation ax²-6x+1= 0 are equal then the value of a
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Answered by
2
Answer:
Since 1 is a root,
3×1^2 + a×1 - 2 = 0
a = -1.
Thus second equation is
-1×(-1x^2+6x)-b=0
i.e., x^2 - 6x -b = 0
This equation has equal roots, so discriminant = 0.
(-6)^2-4×1×-b = 0
a = -36/4 = -9
Step-by-step explanation:
Answered by
2
Answer:
ax²-6x+1=0
a 6x-x²+1=0
a 5x² +1=0
5ax²+1=0
6ax²
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