Question

If the roots of quadratic equatron kx²-5x+k=0 are real and equal, the value of kis
(a)≠ 5 (b)≠5/2 (c)≠2/5 (d)≠2​

Answer 1

Answer:

not equal to 5by 3

Step-by-step explanation:

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Answer 2

Answer:

• Given a Quadratic equation
• $kx^{2} - 5x + k = 0$

A/Q ,we have to find the value of the K for which the given Quadratic have real and equal roots ✓

So, we can determine its value I,e the value of K by using the determinant formula which is given by

$b^{2} -4ac$

But there is a condition that the value of the will be such for that the Given Quadratic equation have roots which is real and equal ✓

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So the for the real and equal roots

$b^{2} - 4ac = 0$

I,e discriminent is equal to 0✓

Let us not find the value of K which is as follows✓

$= > b^{2} - 4ac = 0 \\ here \: a = k \: \: \: b = - 5 \: \: \: and \: c = k$

now we will put the values of a,b, and c in the equation so as to get the value of K ✓

$= > ( - 5)^{2} - 4 \times k \times k = 0 \\ \\ = > 25 - 4k^{2} = 0 \\ \\ = > - 4k ^{2} = - 25 \\ \\ = > 4k ^{2} = 25 \\ \\ > k ^{2} = \frac{24}{4} \\ \\ = > k = \sqrt{ \frac{25}{4} } \\ \\ = > k = \frac{5}{2}$

$the \: value \: \: of \:the \: k \: is \: \frac{5}{2}$✓