Question

If the roots of the equation 12x 2 + mx + 5 = 0 are real and different then m is equal to : ___

Answer 1

Answer:

m = -4√15 , m = 4√15

Step-by-step explanation:

12x^2 + mx + 5 = 0

if roots are real and different

d = 0

b^2 - 4ac = 0

a = 12 , b = m , c = 5

m^2 - 4× 12×5 = 0

m^2 - 240 = 0

m^2 = 240

m = √240

m = +- 4√15

m = 4√15 , m = - 4√15

Answer 2

Answer:

The values of m are $+4\sqrt{5} ,-4\sqrt{5}$

Step-by-step explanation:

Given:

The roots of the equation $12x^2+mx+5=0$ are real and different

We need to find the value of m

As we know when the roots are real and different then the discriminant is zero

So we get as

$m^2-4(12)(5)=0\\\\m^2=240\\\\m=+4\sqrt{5}$or

$m=-4\sqrt{5}$