Math, asked by dikshyasupreet1440, 11 months ago

If the roots of the equation 12x2 + mx + 5 = 0 are in the ratio 3:2, then m equals ________

Answers

Answered by gyan9724702
2

Step-by-step explanation:

12*2+mx+5=0

So, ratio 3:2 then m=3/2

So, m=3

24+3x+5=0

27+3x=0

27=-3x

X= - 9

Answered by raguld
2

Answer:

m = -16

Step-by-step explanation:

We know that, Roots of the quadrilaterals X1 & X2, for a equation Ax^2 + Bx + C = 0 can be written as

X1 + X2 = -(B/A)

(X1)(X2) = (C/A)

Thus X1 + X2 = -(m/12)_______1

X1 x X2 = 5/12_______2

X1/ X2 = 3/2 (given)______3

Substituting 3 in 2

(3/2)X2 x X2 = 5/12

(X2)^2= 10/36 = 5/18

X2 = 0.527

X1 = 0.790

Going back to 1

0.790 + 0.527 = -(m/12)

m = - 12 x 1.317

m = -15.80 ~ - 16

Similar questions