Question

If the roots of the equation 4x²-kx+1=0 are equal, then the value of k

Answer 1

Answer:

$\alpha + \alpha = \frac{k}{4} \\ = 8\alpha = k \\ { \alpha }^{2} = \frac{1}{4} \\ \alpha = \binom{ + }{ - } \frac{1}{2}$

k=8alpha

k=8*1/2 or k=8*-1/2

k=4 or k= -4

Answer 2

Step-by-step explanation:

given Quadratic equation is

4x²-kx+1=0 roots are Real and equal

we have to find value of k.

Here a=4,b=-k,c=1

As we know

$d = {b}^{2} - 4ac$

substitute values of a,b,c

${k}^{2} - 4 \times 4 \times 1$

given equation have real and equal roots,for D=0

${k}^{2} - 16 = 0$

$k = \sqrt{16}$

$k = 4$

Therefore value of k is 4

#SPJ3