Question

if the roots of the equation 4xcube-12xsquare+11x+k=0 are inA.P.Then find K value

Answer 1

4x^3'-12x^2+11x+k =0

• (x+y+z)= -b/a = -(-12/4)= 12/4 = 3
• in Ap, 2y=x+z
• x+y+z=3
• y+2y=3
• 3y=3y
• y=1
• put f(1)=0
• then we get ; 4-12+11+k=0
• 4-1+k=0
• 3+k=0
• k=-3

Answer 2

Answer:

Step-by-step explanation:

4x^3'-12x^2+11x+k =0

   (x+y+z)= -b/a = -(-12/4)= 12/4 = 3

   in Ap, 2y=x+z

   x+y+z=3

   y+2y=3

   3y=3y

   y=1

   put f(1)=0

   then we get ; 4-12+11+k=0

   4-1+k=0

   3+k=0

   k=-3