If the roots of the equation a ( b - c ) x2 + b ( c - a )x + c( a - b ) = 0 are equal, then a, b, c are in
a) A.P
b) G.P
c) H.P
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as roots are equal discriminant is zero
b²(c-a)²=4ac(b-c)(a-b)
c²b²+a²b²-2acb²=4ac(ab-b²-a+bc)=4a²bc-4ab²c-4a²c+4abc²
solve it
then u will find that
b²(c-a)²=4ac(b-c)(a-b)
c²b²+a²b²-2acb²=4ac(ab-b²-a+bc)=4a²bc-4ab²c-4a²c+4abc²
solve it
then u will find that
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