If the roots of the equation a(b-c)x2+(b-c)x+(c-a)has equal roots prove that2a+b+c
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Answer:
Step-by-step explanation:
a(b-c)x^2 +(b-c)x + (c-a) = 0
it has equal roots
so
(b-c)^2 = 4 a(b-c)(c-a)
b-c = 4a (c-a)
4a = (b-c)/(c-a)
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