If the roots of the equation (a-b)x^2 +(b-c)x+(c-a) =0 then prove that b+c=2a
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Answer:
I think the question is not complete. I will solve this question by assuming the two roots are equal.
Step-by-step explanation:
If two roots of this equation are equall then D=(b-c)^2-4(a-b)(c-a)=0;
or,{(a-b)+(c-a)}^2-4(a-b)(c-a)=0;
or, {(a-b)-(c-a)}^2=0;
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