if the roots of the equation a minus b into X square + b minus C Into X + c minus A is equal to zero are equal prove that twice a is equal to b + c
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Answered by
52
Answer:
b + c = 2a
Step-by-step explanation:
If the roots of the equation a minus b into X square + b minus C Into X + c minus A is equal to zero are equal prove that twice a is equal to b + c
(a - b)x² + (b-c)x + (c-a) = 0
Roots are equal if
(b-c)² = 4(a-b)(c-a)
=> b² + c² - 2bc = 4(-a² + ab + ac - bc)
=> b² + c² + 2bc = -4a² + 4a(b + c)
=> (b + c)² = -4a² + 4a(b + c)
=> (b + c)² - 2a(b+c) = -4a² + 2a(b + c)
=> (b + c)(b + c - 2a) = 2a(b + c - 2a)
=> (b + c + 2a)(b + c - 2a) = 0
=> b + c = 2a
Answered by
11
Answer:
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