If the roots of the equation (a2 + b2) x2 – 2(ac + bd) x + (c2 + d2) = 0 are equal, prove that a/b
=c / d
plz ans fast
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Answer:
Step-by-step explanation:
You only solve that (b square - 4ac=0)
Answered by
0
Answer:
Step-by-step explanation:
(a²+b²)x²-2(ac+bd)x+(c²+d²)=0
a=a²+b²
b= -2ac-2bd
c=c²+d²
D=b²--4ac
since the roots are equal D=0
0=b²-4(ac)
0=(-2ac-2bd)²-4{(a²+b²)(c²+d²)}
0=4a²c²+4b²d²+8abcd-4{a²c²+a²d²+b²c²+b²d²}
0=4a²c²+4b²d²+8abcd-4a²c²-4a²d²-4b²c²-4b²d²
0=8abcd-4a²d²-4b²c²
0=2abcd-a²d²-b²c²
0=a²d²+b²c²-2abcd
0=(ad-bc)²
0=ad-bc
ad=bc
a/b=c/d
hence proved
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