Question

If the roots of the equation (ax^2+15x+6=0) are inverse of each other, then value of a is

Answer 1

We Know that The Quadratic Equation is

$a {x}^{2} + bx + c = 0$

Then,

• Sum Of Roots $= \frac{ - b}{a}$

• Products Of Root $= \frac{c}{a}$

Given Equation:-

• $ax^2+15x+6=0$
• Roots are Inverse of each Other.

To Find:-

• The Value of a.

Solution:-

Let Other Zero be $\alpha$

∴ The Other Zero is $\frac{1}{ \alpha }$

Now, according to the Question:-

$\alpha \times \frac{1}{ \alpha } = \frac{6}{a}$

$= > \frac{ \alpha }{ \alpha } = \frac{6}{a}$

$= > 1 = \frac{6}{a}$

$= > a = 6$

Answer 2

Step-by-step explanation:

hope the above attachment will help you