If the roots of the equation ax2 + 2bx + c = 0 are imaginary, then prove
that the roots of the equation ay2 + 2(a + b)y + (a + 2b + c) = 0 are
also imaginary. (Here a, b, c are real numbers)
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Step-by-step explanation:
ax^2+2(a+b)x + (a +2b + c)
0>[2(a+b)]^2-4a(a+2b+c)
0>4b^2-4ac
0>b^2-ac___1
Now
ax^2+2bx+c=0
Then
D=b2-4ac
=4b^2-4.a.c
=4(b^2-ac)
From eq.1
D=imaginary roots[0>b^2-ac]
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