Question

If the roots of the equation ax² +bx+c =0 are in the ratio 3:5, then​

Answer 1

Step-by-step explanation:

x=

2a

−b±

b

2

−4ac

x=

2a

−b±

D

d

2

=b

2

−4ac⇒d=±

D

x=−

2a

b

±

2a

d

x

1

=−

2a

b

+

2a

d

x

2

=−

2a

b

−

2a

d

Given,

x

2

x

1

=

4

3

−(b+d)

d−b

=

4

3

4(d−b)=3[−(b+d)]

4d−4b=−3b−3d

b=7d

⇒b

2

=49d

2

b

2

=49(b

2

−4ac)

48b

2

=196ac

12b

2

=49ac

Answer 2

Step-by-step explanation:

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