If the roots of the equation (b-c) x2 (c-a) x (a-b) =0 are equal , then prove that 2b=ac.
VikasVerma11:
Please send the photo of the que. with the question
is this x sign meant for multiplication?
cuz I can't read what is the exact polynomial given
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Question :- If the roots of the equation (b-c)x²+(c-a)x +(a-b) = 0 are equal,then prove that 2b=a+c.help me !
If the roots of quadratic equation are equal, discriminant is 0 .
b² - 4ac = 0
(c-a) ² - 4 ( b-c) (a - b ) = 0
c²+a²-2ac -4 { ab-b²-ac+bc} = 0
c²+a²-2ac-4ab+4b²+4ac-4bc= 0
a²+c²+(-2b)²+2(a)(c) +2(-2b)(a) +2(-2n)(c) = 0
( a + c -2b) ² = 0
a+ c -2b = 0
a+c=2b .
Hope helped!
If the roots of quadratic equation are equal, discriminant is 0 .
b² - 4ac = 0
(c-a) ² - 4 ( b-c) (a - b ) = 0
c²+a²-2ac -4 { ab-b²-ac+bc} = 0
c²+a²-2ac-4ab+4b²+4ac-4bc= 0
a²+c²+(-2b)²+2(a)(c) +2(-2b)(a) +2(-2n)(c) = 0
( a + c -2b) ² = 0
a+ c -2b = 0
a+c=2b .
Hope helped!
it was correct!!!!!
Answered by
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If the roots of quadratic equation are equal, discriminant is 0.
b2 - 4ac = 0
(c-a) 2 - 4 (b-c) (a - b) = 0
c2+a?-2ac -4 ( ab-b²-ac+bc) = 0
c?+a-2ac-4ab+4b2+4ac-4bc=0
a+c++(-2b)2+2(a)(c) +21-2b)(a) +2(-2n)(c) = 0
(a+c-2b) 2 = o
a+c-2b = 0
a+c=2b.
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