if the roots of the equation given below are equal then the value of c is?
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hey there is your answer
- 3xsquare – 4x + c = 0
- 3xsquare – 4x + c = 03xsquare–3xc–xc+c=0
- 3xsquare – 4x + c = 03xsquare–3xc–xc+c=03x(x–c)–1(x–c)=0
- 3xsquare – 4x + c = 03xsquare–3xc–xc+c=03x(x–c)–1(x–c)=0(3x–1)(x–c)=0
- 3xsquare – 4x + c = 03xsquare–3xc–xc+c=03x(x–c)–1(x–c)=0(3x–1)(x–c)=03x–1=0
3xsquare – 4x + c = 03xsquare–3xc–xc+c=03x(x–c)–1(x–c)=0(3x–1)(x–c)=03x–1=0X=1/3......(i)
3xsquare – 4x + c = 03xsquare–3xc–xc+c=03x(x–c)–1(x–c)=0(3x–1)(x–c)=03x–1=0X=1/3......(i) put equation 1 in x-c:
3xsquare – 4x + c = 03xsquare–3xc–xc+c=03x(x–c)–1(x–c)=0(3x–1)(x–c)=03x–1=0X=1/3......(i) put equation 1 in x-c:1/3–c=0
3xsquare – 4x + c = 03xsquare–3xc–xc+c=03x(x–c)–1(x–c)=0(3x–1)(x–c)=03x–1=0X=1/3......(i) put equation 1 in x-c:1/3–c=0–c=–1/3
So, c=1/3
hope it's helpful for you..
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