Math, asked by abhyudaysinghbhadaur, 6 months ago

if the roots of the equation (m +1) (x²-bx)=(m-1)(ax-c)
are equal in magnitude and opposite sign, then value of
m is

Answers

Answered by Piyushkhathuriya007
0

Answer:

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10th

Maths

Quadratic Equations

Nature of Roots

If the equation x^2-bx/ax ...

MATHS

If the equation

ax−c

x

2

−bx

=

m+1

m−1

has roots equal in magnitude but opposite in sign, then m=

HARD

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VIDEO EXPLANATION

ANSWER

Consider,

ax−c

x

2

−bx

=

m+1

m−1

⇒(m+1)x

2

−b(m+1)x=(m−1)(ax−c)

⇒(m+1)x

2

+((a−b)−(a+b)m)x+c(m−1)=0

Given roots are equal in magnitude and opposite in sign,

Then, sum of roots =0=

m+1

(a−b)−(a+b)m

⇒m=

a+b

a−b

Hence, option 'C' is correct

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